Coding
206. Reverse Linked List
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題目敘述
Given the head of a singly linked list, reverse the list, and return the reversed list.
Example 1

Input: head = [1,2,3,4,5] Output: [5,4,3,2,1]
Example 2

Input: head = [1,2] Output: [2,1]
Example 3
Input: head = [] Output: []
ListNode 的 class 內容
// Definition for singly-linked list.
public class ListNode {
int val;
ListNode next;
ListNode() {}
ListNode(int val) { this.val = val; }
ListNode(int val, ListNode next) { this.val = val; this.next = next; }
}
解題思路
Solution
class Solution {
public ListNode reverseList(ListNode head) {
ListNode prev = null;
ListNode curr = new ListNode();
ListNode next = new ListNode();
curr = head;
while(curr != null){
next = curr.next;
curr.next = prev;
prev = curr;
curr = next;
}
return prev;
}
}