Coding

1658. Minimum Operations to Reduce X to Zero

2023-09-20 2 min read

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題目敘述

You are given an integer array nums and an integer x. In one operation, you can either remove the leftmost or the rightmost element from the array nums and subtract its value from x. Note that this modifies the array for future operations.

Return the minimum number of operations to reduce x to exactly 0 if it is possible, otherwise, return -1.

Example 1

Input: nums = [1,1,4,2,3], x = 5 Output: 2 Explanation: The optimal solution is to remove the last two elements to reduce x to zero.

Example 2

Input: nums = [5,6,7,8,9], x = 4 Output: -1

Example 3

Input: nums = [3,2,20,1,1,3], x = 10 Output: 5 Explanation: The optimal solution is to remove the last three elements and the first two elements (5 operations in total) to reduce x to zero.

解題思路

Solution

public class Solution {
    public int minOperations(int[] nums, int x) {
        int total = 0;
        for (int num : nums) {
            total += num;
        }

        int target = total - x;
        int left = 0;
        int n = nums.length;
        int maxWindow = -1;
        int sum = 0;

        for (int right = 0; right < n; right++) {
            sum += nums[right];

            while (sum > target && left <= right) {
                sum -= nums[left];
                left++;
            }

            if (sum == target) {
                maxWindow = Math.max(maxWindow, right - left + 1);
            }
        }

        return maxWindow != -1 ? n - maxWindow : -1;
    }
}
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